125x^2+25x-30=0

Solution for 125x^2+25x-30=0 equation:

125x^2+25x-30=0

a = 125; b = 25; c = -30;
Δ = b2-4ac
Δ = 252-4·125·(-30)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-125}{2*125}=\frac{-150}{250}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+125}{2*125}=\frac{100}{250}
=2/5
$